A body falls from a height `h = 200 m` (at New Delhi). The ratio of distance travelled in each `2 sec` during `t = 0` to `t = 6` seconds of the journey is.

Options

A. `1:4:9`
B. `1:2:4`
C. `1:3:5`
D. `1:2:3`

Answer

c

Explanation

The distance travelled from O to A is

`OA=ut+(1)/(2)G(2)^(2)=(1)/(2)g(4)=2g [u=0]`
From A to B is
`AB=(1)/(2)g(4)^(2)-(1)/(2)g(2)^(2)`
`=(1)/(2)g(12)`
B to C
`BC=S_(3)-S_(2)=(1)/(2)g(6)^(2)-(1)/(2)g(4)^(2)`
`BC=(1)/(2)g(36-16)`
`BC=(1)/(2)g(20)`
`OA:AB:BC=((1)/(2)g(4)):(1)/(2)g(12):(1)/(2)g(20)`
`=4:12:20`
`=1:3:5`