A particle starting from rest. Its acceleration (a) versus time (t) is as shown in the figure.
The maximum speed of the particle will be.

Options

A. 110 m/s
B. 55m/s
C. 550m/s
D. 660m/s

Answer

b

Explanation

Here we can see that aeceleration remains positive for the first 11 s from the starts, hencec its speed will keep increasing . Change in speed during 11 s is equal to area under the acceleration - time graph and will also be equal to maxium speed acquired by the particle starts from rest.
`v_("max") = (1)/(2) xx 10 xx 11 = 55 m/s`
Hence option (b) is correct.