Home
Class 11
PHYSICS
A particle is given an initial velocity ...

A particle is given an initial velocity of 20m/s. acceleration of the particle changes with time and its variation is shown in the following figure.

Text Solution

Verified by Experts

The correct Answer is:
6
Area under the acceleration - time graph represents the change in velocity . Area above the time axis is taken as positive and below the time axis , it is taken as negative . To acquire initial velocity again , change in velocity must be zero . If we can extend the graph for 6s then we can see that total area becoms zero due to equal amounts of positive and negative areas. Hence particle acquires back its initial velocity at t = 6s.
Answer is 6 .
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos

  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise COMPETITION FILE (MATRIX MATCH TYPE QUESTIONS )|1 Videos

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Chapter Practice Test|15 Videos

  • OSCILLATIONS

    MODERN PUBLICATION|Exercise Practice Test (For Board Examination)|12 Videos

Similar Questions

Explore conceptually related problems

A particle moves in straight line. Acceleration of particle changes with velocity as showns in graph:

A particle is given an initial velocity of vecu=(3 hati+4 hatj) m//s . Acceleration of the particle is veca=(3t^(2) +2 thatj) m//s^(2) . Find the velocity of particle at t=2s.

Knowledge Check

  • In a linear S.H.M., the acceleration of the particle is zero, when its velocity is

    A
    Zero
    B
    Maximum
    C
    Half of its maximum value
    D
    Minimum

  • Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

    A
    `18 ms^(-2)`
    B
    `12 ms^(-2)`
    C
    `15 ms^(-2)`
    D
    zero

    • Similar Questions

    Explore conceptually related problems

    A particle moves vertically with an upwards initial speed v_0 = 10.5 ms^(-1). If its acceleration varies with time as shown in a-t graph in figure, find the velocity of the particles at t = 4s.

    A particle is moving with initial velocity 1m/s and acceleration a=(4t+3)m/s^(2) . Find velocity of particle at t=2sec .

    A particle is moving with an initial velocity of 2m/s and covers a distance of 20m in 5s. Find (a) acceleration of particle (b) time taken by the particle to attain a velocity of 10m/s.

    The acceleration - time graph of a particle is as shown in figure Initial velocity of particle is 10 m//s Displacement of the particle (in m) at the end of 8 sec is ___ Round off to nearest integer.

    A particle moves vertically with an upward initial speed v_(0) = 5 m//s . If its acceleration varies with time as shwon in a - t graph in the fig. 4.30, find the velocity of the particle at t = 7s .

    The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

    Home
    Profile