The acceleration of a certain simple harmonic oscillator is given by
`a=-(35.28 m//s^(2))cos4.2t`
The amplitude of the simple harmonic motion is

The acceleration of a certain simple harmonic oscillator is given by a = -(15.8 m//s^(2)) cos (2.51 t) . What is the amplitude of the simple harmonic mootion?

The velocity of a certain simple harmonic oscillator is given by v= -(12 m//s) sin [(6.0 "rad"//s)t] . What is the amplitude of the simple harmonic motion?

Define simple harmonic motion (S.H.M)

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+Asinomegat+Bcosomegat Then the amplitude of its oscillation is given by :

The acceleration displacement graph of a particle executing simple harmonic motion is shown in figure. The time period of simple harmonic motion is

A simple harmonic motion is represented by F(t)=10sin(20t+0.5) . The amplitude of the S.H.M. is

STATEMENT-1 : The phase difference between acceleration and velocity in simple harmonic motion is 90^(@) . STATEMENT-2 : The tim e period in case of simple harmonic motion is independent of amplitude of vibration.

The displacement of a particle executing simple harmonic motion is given by y=A_(0)+A sin omegat+B cos omegat . Then the amplitude of its oscillation is given by