Write a Pythagorean triplet whose one member is.(i) 6                      (ii) 14                     (iii) 16                (iv) 18

Explanation

General form= `2 m, m^2-1, m^2+1`

1)If 2m=6,Then m=3 ,`m^2-1`=8,`m^2+1`=10

Triplet=6,8,10

2)If 2m=14,Then m=7,`m^2-1`=48,`m^2+1`=50

Triplet=14,48,50

3)If 2m=16, Then m=8,`m^2-1`=63,`m^2+1`=65.