`t_(1//2)` is the half of a substance then `t_(3//4)` is the time in which substance

The half life of radioactive substance is T. Then the fraction of the substance that has decayed in time t is-

The half life of radioactive substance is T. Then the fraction of the substance that has decayed in time t is-

The half life of a radioactive substance is 4.2 days. Find the time during which 1/8" of the sample will remain undecayed.

The radioactivity of a sample is l_(1) at a time t_(1) and l_(2) time t_(2) . If the half-life of the sample is tau_(1//2) , then the number of nuclei that have disintegrated in the time t_(2)-t_(1) is proportional to

If N_(0) is the original mass of the substance of half - life period t_(1//2) = 5 year then the amount of substance left after 15 year is

If N_(0) is the original mass of the substance of half - life period t_(1//2) = 5 year then the amount of substance left after 15 year is

If N_(0) is the original mass of the substance of half - life period t_(1//2) = 5 year then the amount of substance left after 15 year is

A radioactive substance is subject to the law of natural decay (dv)/(dt)=-kv , where v is the volume of the substance at time t and k is a positive constant. The half-life of the substance is the time it takes for half the substance to disappear. Calcualte the half-life if 20 % of the substance disappeared in 15 years.

Decay constant of a radioactive substance is 69.3 sec^(-1) , find t_(1//16) of the same substance

Decay constant of a radioactive substance is 69.3 sec^(-1) , find t_(1//16) of the same substance.