The number of geometrical isomers of the compound is
`C_(6)H_(5)-CH=CH-CH=CH-COOH`

The number of geometrical isomers of the compound, CH_(3)CH=CH-CH=CHCH_(3) is-

Find the number of geometrical isomers of the given compound . C_(6)H_(5) - CH = CH - CH-CH = CH - CH = CH - COOH

The number of geometrical isomers in the following compound CH_3 -CH=CH-CH=CH-C_2H_5 is

The number of geometrical isomers of the molecule CH_(3)-CH=CH-CH=NH is

No. of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(5)

No.of geometrical isomers possible for the compound CH_(3)-CH=CH-CH=CH-C_(2)H_(4)