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Show that Kp for the reaction, 2H2S(g)...

Show that `K_p` for the reaction,
`2H_2S(g) hArr 2H_2(g) +S_2(g)` is given by the expression
`K_p=(alpha^3P)/((2+alpha)(1-alpha)^2)`
where `alpha` is the degree of dissociation and P is the total equilibrium pressure. Calculate `K_c` of the reaction if `alpha` at 298 k and 1 atm . pressure is 0.055.

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