Factorise:
`-5-10t + 20t ^(2)`

Factorise : t^(9)-512

The angular position of a swinging door is described by theta=5+10t+20t^(2) . Determine the angular position, angular speed and angular acceleration at t=2 s .

The position vector vec(r) of a moving particle at time t after the start of the motion is given by vec(r) = (5+20t)hat(i) + (95 + 10t - 5 t^(2)) hat(j) . At the t = T, the particle is moving at right angles to its initial direction of motion. Find the value of T and the distance of the particle from its initial position at this time.

The displacement s of a moving particle at a time t is given by s=5+20t-2t^(2) . Find its acceleration when the velocity is zero.

The x and y coordinates of the particle at any time are x = 5t - 2t^(2) and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at I = 2s is

Find the roots of the following equations by factorisation. (iii) 0.2t^(2)+0.39t=0.02

In the s-t equations (s=10+20t-5t^(2)) match the following