Home
Class 12
CHEMISTRY
446 g of PbO , 46 g of NO(2) and 16 g of...

446 g of PbO , 46 g of `NO_(2)` and 16 g of `O_(2)` are allowed to react according to the equation :-
`PbO+2NO_(2)+(1)/(2)O_(2)toPb(NO_(3))_(2)`
The amount of `Pb(NO_(3))_(2)` that can be produced is (At . Wt. of Pb =207) :-

Promotional Banner

Similar Questions

Explore conceptually related problems

The conversion of PbO_(2) to Pb(NO_(3))_(2) is

What is the valency of Pb in Pb(NO_(3)_(2) ?

Balance the chemical equations: Pb_3 O_4 to PbO + O_2

Balance the following equation : Pb_3O_4 to PbO + O_2 .

Balance the following equation : PbS + O_2 to PbO + SO_2 .

Balance the following equation : Pb(NO_(3))_(2) to PbO + NO_(2) + O_(2)

The reaction Pb(OH)_(2)+HNO_(3)toPb(OH)NIO_(3)+H_(2)O shows that Pb(OH)NO_(3) is

Classify the reaction (i) 2NO_(2) + 2OH^(-) to NO_(2)^(-)+H_(2)O (ii) 2Pb(NO_(3))_(2) to 2PbO+ 2NO_(2) + (1)/(2) O_(2)

Classify the reaction (i) 2NO_(2) + 2OH^(-) to NO_(2)^(-)+H_(2)O (ii) 2Pb(NO_(3))_(2) to 2PbO+ 2NO_(2) + (1)/(2) O_(2)