A force `F=(3xhati+4hatj)` Newton (where x is in metres) acts on a particle which moves from a position (2m, 3m) to (3m, 0m). Then the work done is

Force F=[3x^2hati+4hatj] N where , x in metres, acts on a particle. How much work is done on the particle as it moves from coordinates (2m,3m) to (3m, 0m)?

A force of (4x^(2)+3x)N acts on a particle which displaces it from x=2m to x=3m. The work done by the force is

A force bar F = (3hat i-4 hat j +b hat k)N is acting on the particle which is moving from point A ( 0-1, 1) m to the point B(2, 2 3) m If net work done by the force on the particle is zero then value of b is