` 6x - 5y - 16 = 0`,
` 7x - 13 y + 10 = 0 `.

The orthocentre of the triangle formed by the lines x - 7y + 6 = 0, 2x - 5y - 6 = 0 and 7x + y - 8 = 0 is

Solve the system: x + y - 2z = 0, 2x - 3y + z = 0, 3x - 7y + 10z = 0, 6x - 9y + 10z = 0.

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find P uu Q

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find Q nn R

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find (P uu R)'

If P = {x | x^2 - 10x + 16 = 0} , Q = {x | x^2 - 7x + 10 = 0} , R = {x | x^2 + 6x - 16 = 0} and x is universal set where x = {-2, -1, 0, 1, 2, 5, 8} then find (Q' nn R')

5x - 4y + 8 = 0 7x + 6y - 9= 0

If the lines 12x + 5y + 16 = 0 and 12 x+ 5y - 10 = 0 are tangent to a circle then the radius is :