If G is the centroid of a `DeltaABC`, then `GA^(2)+GB^(2)+GC^(2)` is equal to

If G is the centroid of DeltaABC then bar(GA)+bar(GB)+bar(GC)=

If G is the centroid of triangle ABC, then vec GA+vec GB+vec GC is equal to a.vec 0 b.3vec GA c.3vec GB d.3vec GC

Consider the following statements I. If G is the centroid of DeltaABC , then GA = GB = GC.II. If H is the orthocentre of Delta ABC , then HA = HB = HC. Which of the statements given above is/are correct ?

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If A,B and C are the vertices of a triangle with position vectors vec(a) , vec(b) and vec(c ) respectively and G is the centroid of Delta ABC , then vec( GA) + vec( GB ) + vec( GC ) is equal to

If G be the centroid of the Delta ABC, then prove that AB^(2)+BC^(2)+CA^(2)=3(GA^(2)+GB^(2)+GC^(2))

If G is centroid of the DeltaABC then bar(GA)+bar(BG)+bar(GC)=

If A, B, C are vertices of a triangle whose position vectors are vec a, vec b and vec c respectively and G is the centroid of Delta ABC, " then " vec(GA) + vec(GB) + vec(GC), is