The moment of inertia of a solid sphere of mass M and radius R, about its diameter is `(2//5)MR^(2)` . Its M.I. about parallel axis passing through a point at a distance (R/2) from its centre is

Prove that moment of inertia of uniform ring of mass M and radius R about its geometric axis is MR^(2)

The moment of inertia of a solid sphere of mass M and radius R about its diameter is I. The moment of inertia of the same sphere about a tangent parallel to the diameter is

The moment of inertia of thin spherical shell of mass M and radius R about a diameter is (2)/(3) MR. Its radius of gyration K about a tangent will be

If moment of inertia of a solid sphere of mass 5kg about its diameter is 50kg m^(2) . Its moment of inertia about its tangent in kg m^(2) is

(a) Find the moment of inertia of a sphere about a tangent to the sphere, given the moment of inertia of the sphere about any of its diameters to be 2 MR^(2)//5, where M is the mass of the sphere and R is the radius of the sphere. (b) Given the moment of inertia of a disc of mass M and radius R about any of its diameters to be (1)/(4)MR^(2) , find the moment of inertia about an axis normal to the disc passing through a point on its edge.

If the moment of inertia of a sphere of mass M and radius R about any diameter is m MR^2 , then, what will be its moment of inertia about any tangent?

If moment of inertia of a solid sphere of mass 5 kg about its diameter is 50 kg m^2 . Its moment of inertia about its tangent in kg m^2 is