The bob of a pendulum of mass `8 mu g` carries an electric charge of `39.2xx10^(-10)` coulomb in an electric field of `20xx10^(3)` volt/meter and it is at rest. The angle made by the pendulum with the vertical will be

The bob of a pendulum of weight 80 mg carries a charge of 2xx10^(-8) C. The bob is at rest in a horizontal electric field of magnitude 2xx10^(4)V.m^(-1) . Determine the tension in the string and angle of the string with the vertical. Given, g=9.8m.s^(-2) .

A pendulum bob of mass 80 mg and carrying a charge of 2xx10^-8 coulomb is at rest in a horizontal uniform electric field of 20,000 V m^-1 . Find the tension in thread of the pendulum and the angle it makes with the vertical.

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A pendulum bob of mass 80mg and carrying a charge of 2xx 10^(-8)C is at rest in a uniform, horizontal electric field of 20k Vm^-1. Find the tension in the thread.

A pendulum bob of mass 80mg and carrying a charge of 2 times10^(-4) coulomb is at rest in a uniform horizontal electric field of 20kV/m .The tension in the thread of the pendulum is x times 10^(-4) N.Find value of x?

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 2000V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 2000V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

The bob of a simple pendulum has mass 2g and a charge of 5.0muC . It is at rest in a uniform horizontal electric field of intensity 200V//m . At equilibrium, the angle that the pendulum makes with the vertical is: (take g=10m//s^(2) )

A uniform electric field of 3xx10^4 N/C is applied iin a horizontal direction . A pendulum bob of mass 90 mg and carrying a charge of 1.5xx10^(-8) C is suspended through a string of length 1m. Calculate tension developed in the string and the angle made by the string with the vertical .