A tyre pumped to a pressure `3.375 atm "at" 27^(@)C` suddenly bursts. What is the final temperature `(gamma = 1.5)`?

A tyre pumped at a pressure of 3.375 atm and at 27^(@)C suddenly bursts. What is the final temperature? (gamma=1.5)

A tyre is pumped to a pressure of 3.375 atmospheres and at 27^@C suddently bursts.What is the final temperature? (gamma=1.5) .

A tyre pumped to a pressure of 3.375 atmosphere and at 27^@C suddenly bursts . Calculate the temperature of escaping air . (y = 1.5)

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

A tyre pumped to a pressure of 3 atmospheres suddenly bursts. Calculate the fall in temperature due to adiabatic expansion. The temperature of air before expansion is 27^(@)C and value of gamma = 1.4 .

The pressure of the air inside the motor tyre is 2 atmosphere and the temperature is 27^@C . If it suddenly bursts, the final temperature will be (gamma=1.4) :

Air (gamma = 1.4 ) is pumped at 20atm pressure in a motor tyre at 20^@C . If the tyre suddenly bursts, what would be the temperature of the air coming out of the tyre. Neglect any mixing with the atmoshpheric air.

Air (gamma = 1.4 ) is pumped at 2atm pressure in a motor tyre at 20^@C . If the tyre suddenly bursts, what would be the temperature of the air coming out of the tyre. Neglect any mixing with the atmospheric air.