निम्नलिखित नाभिकीय अभिक्रियाओं में X को पहचानिएः
`._(11)^(23)Na+._(0)^(1)nto._(-1)^(0)beta+X`

If beta +2 int_0^(1) x^(2)e^(-x^(2)) dx = int_0^(1) e^(-x^(2) , then beta =

Neon -23 decays in the following way ""_(10)^(23)Nerarr""_(11)^(23)Ne+""_(-1)e^0+barv. Find the minimum and maximum kinetic energy that the beta particle (""_(-1)e^(0)) can have . The atomic masses of ""^(23)Ne and ""^(23)Na are 22.9945 u and 22.9898 u, respectively.

The symbol x in the following equation is ""_(11)Na^(23)+""_(1)H^(1) rarr ""_(12)Mg^(23)+x

If m gt 0, n gt 0 , the definite integral l=int_(0)^(1)x^(m-1)(1-x)^(n-1)dx depends upon the vlaues of m and n and is denoted by beta(m,n) , called the beta function. E.g. int_(0)^(1)x^(4)(1-x)^(5)dx=int_(0)^(1)x^(5-1)(1-x)^(6-1)dx=beta(5, 6) and int_(0)^(1)x^(5//2)(1-x)^(-1//2)dx=int_(0)^(1)x^(7//2-1)(1-x)^(1//2-1)dx=beta((7)/(2),(1)/(2)) . Obviously, beta(n, m)=beta(m, n) . If int_(0)^(n)(1-(x)/(n))^(n)x^(k-1)dx=R beta(k, n+1) , then R is equal to