if `Delta=|[x-3,2x+1,2],[3x+2,x+2,1],[5x+1,5x+4,5]|` then `Delta ` is:

if Delta=det[[x-3,2x+1,23x+2,x+2,15x+1,5x+4,5]] then Delta is:

If Delta_1=|(7,x,2),(-5,x+1,3),(4,x,7)|, Delta_2=|(x,2,7),(x+1,3,-5),(x,7,4)| , then Delta_1+Delta_2=0 for :

If x=-2 and Delta=|(x+y,x,x),(5x+4y,4x,2x),(10x+8y,8x,3x)| then numerical value of Delta is

If Delta = |(10,4,3),(17,7,4),(4,-5,7)|, Delta_(2) = |(4,x +5,3),(7,x +12,4),(-5,x -1,7)| such that Delta_(1) + Delta_(2) = 0 , then

If Delta_(1) = |(7,x,2),(-5,x +1,3),(4,x,7)| and Delta_(2) = |(x,2,7),(x +1,3,-5),(x,7,4)| , then the value of x for which Delta_(1) + Delta_(2) = 0 , is

If Delta_(1) = |(7,x,2),(-5,x +1,3),(4,x,7)| and Delta_(2) = |(x,2,7),(x +1,3,-5),(x,7,4)| , then the value of x for which Delta_(1) + Delta_(2) = 0 , is

If y=2x^(2)-3x+5, x=1, deltax=0.03 , then delta y ~~...