गणितीय आगमन सिद्धांत से सिध्द कीजिए कि n के सभी धन पूर्णांक मानो के लिए :
`2+5+8+11+......+(3n-1)=(1)/(2)n(3n+1)`

If ^(n+5)P_(n+1)=(11(n-1))/(2)n+3P_(n), find n

Assume that f(1) = 0 and that for all integers m and n f(m+n) = f(m) + f(n) + 3(4mn-1) then f(19) = मान लें कि f(1)= 0 और कि सभी पूर्णांकों के लिए m और n f(m+n) = f(m)+f(m)+3(4mn-1) फिर f(19)

1.3+3.5+5.7+......+(2n-1)(2n+1)=(n(4n^(2)+6n-1))/(3)

Prove by mathematical induction 5 + 8 + 11 + ...+ (3n-+2)= 1/2 n(3n + 7).

Find n, ""^(n+5)P_(n+1)=(11)/(2)(n-1)*""^(n+3)P_(n).

Find n, ""^(n+5)P_(n+1)=(11)/(2)(n-1)*""^(n+3)P_(n).

Find n, ""^(n+5)P_(n+1)=(11)/(2)(n-1)*""^(n+3)P_(n).

Prove the following by the principle of mathematical induction: 2+5+8+11++(3n-1)=(1)/(2)n(3n+1)