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Collission Of Particles Part 2...

Collission Of Particles Part 2

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If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

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A particle of mass m is released from rest and follow a particle part as shown Accuming that the displacement of the mass from the origin is small which graph correctlly depicts the position of the particle as a function of time?

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In part a of the figure, particles 1 and 2 move around point O in circles with radii 2 m and 4 m. In part b, particles 3 and 4 travel along straight lines at perpendicular distances of 4 m and 2 m from point O. Particle 5 moves directly away from O. All five particles have the same mass and the same constant speed. (a) Rank the particles according to the magnitudes of their angular momentum about point O, greatest first. (b) Which particles have neagtive angular momentum about point O?

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Questions Part -1|Questions Part -2|Summary

A particle starts from rest with acceleration 2m//s^(2) . The acceleratioin of the particle of the particle descreases down to zero uniformly during time -interval of 4s . The velocity of particle after 2s is

A particle executes simple harmonic motion. The amplitude of vibration of particle is 2 cm. The displacement of particle in one time period is