Let `4alpha int_(-1)^2 e^(-alpha|x|) dx = 5`, then `alpha` =

[" Let "4 alpha int_(-1)^(-)e^(-alpha|x|)dx=5" then "alpha=],[[" (A) "ln2," (B) "ln sqrt(2)],[" (C) "ln(3)/(4)," (D) "ln(4)/(3)]]

The value of alpha for which 4alphaint_(-1)^(2)e^(-alpha|x|)dx=5 is :

If int _0^1e^(x^2)(x-alpha)dx=0 , then

If int_(0)^(1)e^(x^(2))(x-alpha)dx=0, then

If int_(0)^(1) e^(x^(2))(x-alpha)dx=0 then

If int_(0)^(1)e^(x^(2)) (x-alpha)dx=0 then

If I = int_0^2 (e^x)^4 (x - alpha) dx = 0 , then alpha lies in the interval

If 0 le alpha le 2pi and int_(0)^(alpha)cos x dx = cos 2alpha , the : alpha =

If I=int_(0)^(2)e^(x^(4))(x-alpha)dx=0 , then alpha lies in the interval

If I=int_(0)^(2)e^(x^(4))(x-alpha)dx=0 , then alpha lies in the interval-