`tan[1/2(sin^(- 1)((2x)/(1+x^2))+cos^(- 1)((1-y^2)/(1+y^2))]`

tan[1/2sin^(-1)((2x)/(1+x^(2)))-1/2cos^(-1)((1-y^(2))/(1+y^(2)))]=

Find the values of the following tan frac(1)(2) [sin^(-1)((2x)/(1+x^2))+ cos^(-1) ((1-y^2)/(1+y^2))],|x| lt 1, y gt 0 and x y lt 1

Simplity tan{1/2sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)(1-y^(2))/(1+y^(2))} , if xgtygt1 .

Find the value of tan{1/2 sin^-1((2x)/(1+x^2)) + 1/2cos^-1 ((1-y^2)/(1+y^2))}

Prove that tan{1/2sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)((1-y^(2))/(1+y^(2)))}=(x+y)/(1-xy) , where |x| lt 1,y gt 0 and xy lt 1 .

Find the value of: tan1/2[sin^(-1)(2x)/(1+x^2)+cos^(-1)(1-y^2)/(1+y^2)],|x| 0 and x y" "<" "1

tan[1/2Sin^(-1)((2x)/(1+x^(2)))-1/2Cos^(-1)((1-y^(2))/(1+y^(2)))]=

tan{(1/2)sin^(-1)((2x)/(1+x^(2)))+1/2cos^(-1)((1-y^(2))/(1+y^(2)))} .

Express the value of tan{1/2 "sin"^(-1) (2x)/(1+x^2)+1/2 "cos"^-1 (1-y^2)/(1+y^2)} in simplest form.

Find the value of tan { 1/2 sin^(-1) ((2x)/(1+x^(2))) + 1/2 cos^(-1) ((1-y^(2))/(1+ y^(2)))}