A balloon starts rising with constant acceleration `2 m//s^(2)` from ground at `t=0s`. A stone is dropped at `t=5s`. S-t graph for the given situation is shown in figure answer the following
`t_(1)` is

A balloon starts rising with constant acceleration 2 m//s^(2) from ground at t=0s . A stone is dropped at t=5s . S-t graph for the given situation is shown in figure answer the following t_(2) is

A balloon starts rising with constant acceleration 2 m//s^(2) from ground at t=0s . A stone is dropped at t=5s . S-t graph for the given situation is shown in figure answer the following Q. The maximum hight reached by the stone is

A balloon starts rising from ground from rest with an upward acceleration 2m//s^(2) . Just after 1 s, a stone is dropped from it. The time taken by stone to strike the ground is nearly

A balloon starts rising from ground from rest with an upward acceleration 2m//s^(2) . Just after 1 s, a stone is dropped from it. The time taken by stone to strike the ground is nearly

A balloon starts rising upwards with constant acceleration a and afrer time t_(0) , second, a packet is dropped from it which reaches the ground aftre t seconds of dropping . Derermine the value of t .

A balloon starts rising upwards with constant acceleration a and afrer time t_(0) , second, a packet is dropped from it which reaches the ground aftre t seconds of dropping . Derermine the value of t .

A balloon starts rising from thee ground with an acceleration of 1.25 m//s^(2) . After 8 s, a stone is released from the balloon. The stone will (taking g = 10 ms^(-2) )

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon starts rising from the ground with an acceleration of 1.25m//s^2 . After 8s stone is released from the ballon. What distance the stone will cover?