`log ((dy)/(dx)) =2x +3y `

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log((dy)/(dx))=2x+3 A) y=log(2x+3)+c B) 2y=e^(2x+3)+c C) sqrty=log(2x+3)+c D) 2e^(y)+3=logy+c

Find the particular solution of log (dy/dx)= 2 x + 3y given that x = 0, y= 0 .

y dx + x log ((y)/(x))dy - 2xdy = 0

Degree of the differential equation log (dy/dx)^1/2 = 3x + 4y is :