[" 48.Heat of formation of "H_(2)O(g)" at "1" atm and "25^(@)C" is "],[-243kJ.Delta E" for the reaction "H_(2)(g)+30JK^(-1)mol^(-1)(1)/(2)],[O(g)longrightarrow H_(2)O(g)" at "25^(@)C" is "],[[" (a) "241.8kJ," (b) "-241.8kJ],[" (c) "-243kJ," (d) "243kJ]]

Heat of formation of H_(2)O(g) at 1 atm and 25^(@)C is -243KJ . DeltaE for the reaction H_(2)(g)+30JK^(-1)mol^(-1)(1)/(2) O(g)rarrH_(2)O(g) at 25^(@)C is

Heat of formation of H_2O(g) at 1 atm and 25^@C is -243 kJ. triangleE for the reaction, H_2(g)+1/2O(g)rarrH_2O(g) at 25^@C is

Heat of formation of H_(2)O_((g))" at "25^(@)C is -243 kJ. Delta U for the reaction H_(2(g))+(1)/(2) O_(2(g)) rarr H_(2)O_((g))" at "25^(@)C is

Calculate Delta H-DeltaU at 25^@C for the reaction: H_2(g)+( 1/2)O_2(g) = H_2O(l) .

Standard entropies of H_(2)(g),O_(2)(g) " and "H_(2)O(l) are respectively 126.6, 201.2 and 68JK^(-1)mol^(-1) Determine DeltaS" for "2H_(2)(g)+O_(2)(g) to 2H_(2)O(l) at 25^(@)C .

If Delta G_(298K) for the reaction 2H_(2(g. 1atm)) + O_(2(g. 1atm)) rarr 2H_(2)O_((g.1atm)) is -240kJ , what will be Delta G_(298K) for the reaction H_(2)O_((g.0.2 atm)) rarr H_(2(g.4atm)) + (1)/(2) O_(2(g.0.26atm))

If Delta G_(298K) for the reaction 2H_(2(g. 1atm)) + O_(2(g. 1atm)) rarr 2H_(2)O_((g.1atm)) is -240kJ , what will be Delta G_(298K) for the reaction H_(2)O_((g.0.2 atm)) rarr H_(2(g.4atm)) + (1)/(2) O_(2(g.0.26atm))

Calculate the enthalpy of formation of Delta_(f)H for C_(2)H_(5)OH from tabulated data and its heat of combustion as represented by the following equaitons: i. H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(g), DeltaH^(Theta) =- 241.8 kJ mol^(-1) ii. C(s) +O_(2)(g) rarr CO_(2)(g),DeltaH^(Theta) =- 393.5kJ mol^(-1) iii. C_(2)H_(5)OH (l) +3O_(2)(g) rarr 3H_(2)O(g) + 2CO_(2)(g), DeltaH^(Theta) =- 1234.7kJ mol^(-1) a. -2747.1 kJ mol^(-1) b. -277.7 kJ mol^(-1) c. 277.7 kJ mol^(-1) d. 2747.1 kJ mol^(-1)

Changes in enthalpy for the reaction : 2H_(2)O_(2)(g) rarr 2H_(2)O (l) + O_(2)(g) if heat of formation of H_(2)O_(2)(l) and H_(2)O(l) are -188 kJ mol^(-1) and -286 kJ mol^(-1) respectively is