`int x^3/(2x+1) dx`

int(4x+3)/(2x+1)dx

int(x^3)/(x^2+x+1)dx=

int 1/(3x^2+x+1) dx

int(2x+3)/(3x+1)dx

int(x^(2)+3)/(x-1)dx

(i) int (3x^2)/(x^6+1) dx (ii) int (3x)/(1+2x^4) dx

int(x^3(2x-1))/(x-1)dx

int_2^3 x/(x^2+1)dx

Integrate the following (1) intx^(-3/2)dx (2) intsin60^(@)dx (3) int(1)/(10x)dx (4) int(2x^(3)-x^(2)+1)dx

int(2x+3)/(5x-1)*dx