If `Q(h,k)` is the foot of the perpendicular of `P(x_(1),y_(1))` on the line `ax+by+c=0` then prove that `(h-x_(1)),a=(k-y_(1)),b=-(ax_(1)+by_(1)+c):(a^(2)+b^(2))`.

If Q(h,k) is the foot of the perpendicular from P(x_(1) ,y_(1)) on the line ax + by+ c=0 then Q(h,k) is

If Q(h,k) is the foot of the perpendicular from P(x_(1),y_(1)) on the line ax+by+c=0 then (h-x_(1))/(a)=(k-y_(1))/(b) =_____ .

If (h,k) is the foot of the perpendicular from (x_(1),y_(1)) to the line ax+by+c=0, (a!=0,b!=0) then (h-x_(1))/(a)=(k-y_(1))/(b)=(-(ax_(1)+by_(1)+c))/(a^(2)+b^(2)) Find the foot of the perpendicular from (-1,3) to the line 5x-y=18

If Q(h,k) is the image of the point P(x_(1),y_(1)) w.r.to the straight line ax+by+c=0 then prove that (h-x_(1)):a=(k-y_(1)):b=-2(ax_(1)+by_(1)+c):a^(2)+b^(2) or (h-x_(1))/(a)=(k-y_(1))/(b)=(-2(ax_(1)+by_(1)+c))/(a^(2)+b^(2)) and find the image of (1,-2) w.r.t the straight line 2x-3y+5=0

Foot of the perpendicular from a point (x_(1),y_(1)) on the line ax + by + c= 0 is given by

If the length of the perpendicular from the point (1, 1) to the line ax-by+c=0 be , show that 1/c + 1/a - 1/b = c/(2ab)

If the length of the perpendicular from the point (1,1) to the line ax-by+c=0 be unity,show that (1)/(c)+(1)/(a)-(1)/(b)=(c)/(2ab)

If theta is the acute angle between the lines with slopes m1 and m2 then tan theta=(m_(1)-m_(2))/(1+m_(1)m_(2)) 2) if p is the length the perpendicular from point P(x1,y1) to the line ax +by+c=0 then p=(ax_(1)+by_(1)+c)/(sqrt(a^(2)+b^(2)))

If the image of the point ( x_1,y_1 ) with respect to the mirror ax+by+c=0 be ( x_2,y_2 ), show that (x_2-x_1)/a=(y_2-y_1)/b=(-2(ax_1+by_1+c))/(a^2+b^2) .