A point source of electromagnetic radiation has an average power output of `800 W`. The maximum value of elecvtric field at a distance `4.0 m` from the source is

A point source of electromagnetic radiation has an average power output of 800W. The mximum value of electric field at a distance 3.5 m from the source will be 62.6 V/m, the maximum value of magnetic field will be -

A point source of electromagnetic radiation has an average power output of 800W . The maximum value of electric field at a distance 3.5m from the source will be 62.6 V/m , the energy density at a distance 3.5 m from the source will be- (in "joule"//m^(3) )

A point source of electromagnetic radiation has an average power output of 800W. (a) Find the maximum value of electric field at a distance 3.5 m from the source. (b) What will be the maximum value of magnetic field? (c) What will be the energy density at a distance at a distance 3.5m from the source?

A point source of electromagnetic radiation has an average power output of1500W. The maximum value of electric field at a distance 3m from this source in Vm^-1 is

A point source of electromagnetic radiaction has average power output of 800 watt. Then find (a) Maximum value of electric field at a distance 3.5m from the source (b) Maximum vatue of magnetic field (c) Average energy density at 3.5 m from the source.

A point source, of electromagnetic radiation has average power output of 800 W. The maximum value electric at a distance 4.0 m from the source is:

A point source of electromagnetic radiation has average power output of 800 watt, then find (a) Maximum value of electric field at a distance 3.5 m from the source (b) Maximum value of magnetic field (c) Average energy density at 3.5 m from the source.

A point source of 2 watt is radiating uniformly in all direction in vacuum. Find the amplitude of electric field at a distance 2m from it-

A mercury lamp is radiating monochromatic light of power 10W.The peak value of electric field strength at a distance of 5m from the lamp is nearly