The lines represents by `ax^2+2hxy+by^2=0` are perpendicular to each other , if

If the lines represented by kx^(2) - 3xy + 6y^(2) = 0 are perpendicular to each other then…..

The two lines represented by 3ax^(2)+5xy+(a^(2)-2)y^(2)=0 are perpendicular to each other for two values of a (b) a for one value of a (d) for no values of a

The two lines represented by 3ax^(2)+5xt+(a^(2)-2)y^(2)=0 are perpendicular to each other for

Find the condition that the one of the lines given by ax^2+2hxy+by^2=0 may be perpendicular to one of the lines given by a'x^2+2h'xy+b'y^2=0

If the slope of one of the lines represented by ax^2+2hxy+by^2=0 is the sqaure of the other , then

If the slope of one of the lines represented by ax^(2)+2hxy+by^(2)=0 is the square of the other , then (a+b)/(h)+(8h^(2))/(ab)=

If the slope of one of the lines represented by ax^(2)+2hxy+by^(2)=0 be the square of the other, then (a+b)/(h)+(8h^(2))/(ab)=

If the slope of one of the lines represented by ax^(2)+2hxy+by^(2)=0 is square of the slope of the other line, then

If the slope of one of the lines represented by ax^(2)+2hxy+by^(2)=0 is the square of the other,then (a+b)/(h)+(8h^(2))/(ab)=4(b)6(c)8(d) none of these