A particle is acted by a force `F=(6t+3t^(2))N` where `t` is in seconds what is impulse in `t=1` to `t=3sec`

A particle is acted upon by a force given by F=(12t-3t^(2)) N, where is in seconds. Find the change in momenum of that particle from t=1 to t=3 sec.

Force applied on a body is given by ltbygt F=(3t^(2)-2t+10) N where t is in seconds. Find impulse imparted in t=0 to t=2 sec.

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The particle

The position of a particle is given by x=2(t-t^(2)) where t is expressed in seconds and x is in metre. The acceleration of the particle is

The angular displacement of a particle is given by theta = t^4 +t^3 +t^2 +1 where ‘t’ is time in seconds. Its angular velocity after 2 sec is

The position of a particle is given by r = 3t hati +2t^(2) hatj +8 hatk where, t is in seconds and the coefficients have the proper units for r to be in meters. (i) Find v (t) and a(t) of the particles. (ii) Find the magnitude and direction of v(t) and a(t) at t = 1s .

The position of a particle is given by the equation f(t)=t^(3)-6t^(2)+9t where t is measured in second and s in meter. Find the acceleration at time t. What is the acceleration at 4 s?

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is

The displacement of a particle is given by y=(6t^2+3t+4)m , where t is in seconds. Calculate the instantaneous speed of the particle.

The acceleration of a particle varies with time t as a=t^(2)+t+2 where t is in seconds. The particle starts with an initial velocity v-3m/s at t=0. find the velocity of the particle at the end of 5s.