The height of a boulder launched from a Roman catap can be described as a function of time according to the following quadratic equation: `h(t)=-16 t ^(2) +224t+240.`
What is the maximum height that the boulder attains ?

The height of a boulder launched from a Roman catap can be described as a function of time according to the following quadratic equation: h(t)=-16 t ^(2) +224t+240. How much time elapese between the moment the boulder is launched and the moment it hits the ground, assuming that the ground is at a height of 0 ?

A model rocket is launched vertically into the air such that its height at any time, t, is given by the function h(t)=-16t^(2)+80t+10 . What is the maximum height attained by the model rocket?

A stone is thrown in upward direction. Its equation is S=80 t-16 t^(2) . The time to attain maximum height is …………. second.

The height of a ball thrown into the air with an initial vertical velocity of 24 fts from a height of 6 feet above the ground is given by the equation: h=16t^(2)+24t+6, where t is the time in seconds,for the ball has been in air. After how many seconds is the ball at a height of 14 feets

A stone thrown vertically upwards rises S ft in t seconds where S =112t-16t ^(2) . The maximum height reached by the stone is

The height h , in feet , of a ball shot upward from a ground level spring gun is described by the formula h=-16t^2+48t . Where t is the time in seconds. What is the maximum height , in feet , reached by the ball ?

The height (in meters) at any time t (in seconds) of a ball thrown vertically varies according to equation h(t)=-16t^(2)+256t . How long after in seconds the ball reaches the hightest point

The height (in meters) at any time t (in seconds) of a ball thrown vertically varies according to equation h(t)=-16t^(2)+256t . How long after in seconds the ball reaches the hightest point

The height (in meters) at any time t (in seconds) of a ball thrown vertically varies according to equation h(t)=-16t^(2)+256t . How long after in seconds the ball reaches the hightest point

A stone thrown vertically upwards satisfies the equations s = 80t –16t^(2) . The time required to reach the maximum height is