If discharge rate is given by `V=(pi Pr^(4))/(8 mu l)` then find out the dimensions of `mu` by taking velocity (v), time (T) and mass (M) as fundamental units.

Young's modulus is Y = stress /strain. Here stress is the force of reaction per unit area and strain is the change of length per unit initial length. Find out dimension of Y. If velocity (V) acceleration (A) and force (F) are taken as the fundamental quantities in place of mass length and time then what will be the dimension of Y ?

Assuming velocity (V) time (T) and force (F) as the fundamental quantities find the dimension of density.

Assuming velocity (V), time (7) and force (F) as the fundamental quantities, find the dimension of density.

Taking velocity, time and force as the fundamental quantities, find the dimensions of mass.

Taking velocity , time and force as the fundamental quantities , find the dimension of mass .

Velocity v is given by v=at^(2)+bt+c , where t is time. What are the dimensions of a, b and c respectively?

Velocity v is given by v=at^(2)+bt+c , where t is time. What are the dimensions of a, b and c respectively?

If force (F), velocity (v) and time (T) are taken as fundamental units, the dimension of mass are .....