`(3 + omega + 3omega^(2))^(4)` का मान है

(3 + 5 omega + 3omega^(2))^(6) =

If 1 , omega , omega^(2) are the cube roots of unity , then (a+ b)^(3) + (a omega + b omega^(2))^(3) + ( a omega^(2) + b omega)^(3) =

(2 + omega + omega ^ (2)) ^ (3) + (1 + omega-omega ^ (2)) ^ (3) = (1-3 omega + omega ^ (2)) ^ (4) = 1

If 1, omega, omega^(2) are three cube roots of unity, prove that (3+ 5omega + 3omega^(2))^(6) = (3 + 5omega^(2) + 3omega)^(6)= 64

If omega is a cube root of unity , then |{:( 1 , omega , 2 omega^(2)) , (2 , 2omega^(2) , 4 omega^(3)) , (3 , 3 omega^(3) , 6 omega^(4)):}| =

(3+omega + 3 omega^(2))^(4)= lambda omega , then value of lambda is :

If omega=(-1+i sqrt(3))/(2) then (3+omega+3 omega^(2))^(4)=

If omega be the imaginary cube root of 1, then the value of (3+omega+3omega^(2))^(4) will be

(3 - omega) ( 3- omega^(2)) ( 3- omega^(4)) (3 - omega^(8)) =