" (iv) "(1)/(2+sqrt(3))" ."

If a = (1)/(2 - sqrt(3)) , b = (1)/(2 + sqrt(3)) , find the value of ((a + b)/(a -b))^(2) .

sqrt((4)/(3))-sqrt((3)/(4))=?(4sqrt(3))/(6) (b) (1)/(2sqrt(3))(c)1(d)-(1)/(2sqrt(3))

cot^(-1)(2+sqrt(3))=

Rationalize the denominator of (1)/(2+sqrt(3))

Rationalise the denominator of (1)/(2+sqrt(3))

Tangents drawn from (2, 0) to the circle x^2 + y^2 = 1 touch the circle at A and B . Then (A) A-= (1/2, sqrt(3)/2) , B -= (-1/2, - sqrt(3)/2) (B) A-= (- 1/2, (-sqrt(3)/2) , B -= (1/2, sqrt(3)/2) (C) A-= (1/2, sqrt(3)/2) , B-= (1/2, - sqrt(3)/2) (D) A-= (1/2, - sqrt(3)/2), B-= (1/2, sqrt(3)/2)

Find the value of (1)/(2+sqrt(3))+(1)/(2-sqrt(3))