In a triangle, ABC, the equation of the ...

In a triangle, ABC, the equation of the perpendicular bisector of AC is `3x - 2y + 8 = 0`. If the coordinates of the points A and B are `(1, -1) & (3, 1)` respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

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In a triangle, ABC, the equation of the perpendicular bisector of AC is `3x - 2y + 8 = 0`. If the coordinates of the points A and B are `(1, -1) & (3, 1)` respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

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