(iv)|[0,1,sec alpha],[tan alpha,-sec alpha,tan alpha],[1,0,1]|

If minor of three-one element (i.e.M_(31)) in the determinant [{:(,0,1,sec alpha),(,tan alpha,-sec alpha,tan alpha),(,1,0,1)]:} is 1 then find the value of alpha (0 le alpha le pi).

If minor of three-one element (i.e.M_(31)) in the determinant [{:(,0,1,sec alpha),(,tan alpha,-sec alpha,tan alpha),(,1,0,1)]:} is 1 then find the value of alpha (0 le alpha le pi).

[[1,-tan alpha],[tan alpha,1]][[1,tan alpha],[-tan alpha,1]]=[[a,-b],[-b,a]] then sec "^(2)alpha

If [[1,-tan alpha],[tan alpha,1]][[1,tan alpha],[-tan alpha,1]]=[[a,-b],[-b,a]] then sec^(2)alpha=

tan2alpha-tanalpha(1+sec2alpha)=

P=[[sec alpha,tan alpha-cot alpha,cos alpha]] and Q=[[-cos alpha,tan alpha-cot alpha,-sec alpha]]

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha + d tan alpha=c , then eliminate alpha from above equations.

If a sec alpha-c tan alpha=d and b sec alpha - d tan alpha=c , then eliminate alpha from above equations.

(sec8 alpha-1)/(sec4 alpha-1)=(tan8 alpha)/(tan2 alpha)