In an equilateral triangle ABC, equation of the sides BC is `x+y-2=0` and the centroid of `DeltaABC` is (0, 0). If points A, B and C are inanticlockwise order, then the equation of side AC is

In an equilateral triangle ABC, equation of the sides BC is x+y-2=0 and the centroid of DeltaABC is (0, 0). If points A, B and C are in anticlockwise order, then the equation of side AC is

In the equilateral triangle ABC, the equation of the side BC is x+y-2=0 and the centroid of DeltaABC is (0, 0). If the points A, B, C are in anticlockwise oder, then the midpoint of the line segment joining A and C is

One vertex of an equilateral triangle is (2,3) and the equation of one side is x-y+5=0. Then the equation to other sides are

One vertex of an equilateral triangle is (2,3) and the equation of one side is x-y+5=0. Then the equations to other sides are

In a triangle,ABC,the equation of the perpendicular bisector of AC is 3x-2y+8=0. If the coordinates of the points A and B are (1,-1)&(3,1) respectively,then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

In DeltaABC , equation of side BC is x+y-6=0, also the circumcentre and orhtocentre are (3, 1) and (2, 2) respectively, then the equation of the circumcircle of DeltaABC is

In DeltaABC , equation of side BC is x+y-6=0, also the circumcentre and orhtocentre are (3, 1) and (2, 2) respectively, then the equation of the circumcircle of DeltaABC is

In a triangle, ABC, the equation of the perpendicular bisector of AC is 3x - 2y + 8 = 0 . If the coordinates of the points A and B are (1, -1) & (3, 1) respectively, then the equation of the line BC & the centre of the circum-circle of the triangle ABC will be

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot

In triangle A B C , the equation of the right bisectors of the sides A B and A C are x+y=0 and y-x=0 , respectively. If A-=(5,7) , then find the equation of side B Cdot