If cosx = `(1)/(2)`and `0 lt x lt 2pi` then solutions are

Assertion (A) : cos x = (-1)/(2) and 0 lt x lt 2pi, "then the solutions are x" = (2pi)/(3), (4pi)/(3) . Reason (R ) : cos is negative in the first and fourth quadrant only

If 0 lt x lt pi/2 then

If 0 lt x lt pi/2 then

If 0 lt x lt pi/2 then

If 0 lt x lt pi /2 then

If 0 lt x lt pi /2 then

If cosx =(-1)/(3) and pi lt x lt (3pi)/(2) Find the value of cos (x/2) , tan (x/2)

If sec x cos 5x + 1 =0, 0 lt x lt 2pi , then x =

cos2x - 5 cosx +3 =0 (0 lt x lt 2pi)