`tan(cos^(- 1)x)=sin(tan^(- 1)2)`

int(cos(tan^(-1)x)+sin(tan^(-1)x))/(1+x^(2))dx=

tan[cos ^(-1){sin(2tan^(-1)2)}] is equal to

int (cos (tan ^ (- 1) x) + sin (tan ^ (- 1) x)) / (1 + x ^ (2)) dx

tan (cos ^(-1) x) = sin (cot ^(-1) ""(1)/(2))

Slove: tan(cos^-1x)=sin(cot^-1""1/2)

The value of tan(sin^(-1)(cos(sin^(-1)x)))tan(cos^(-1)(sin(cos^(-1)x)))." where "x in (0, 1) is equal to

tan (cos ^ (-1) x) = sin ((1) / (2)); then x =

The value of tan(sin^(-1)(cos(sin^(-1)x)))tan(cos^(-1)(sin(cos^(-1)x))), where x in(0,1) is equal to 0(b)1(c)-1(d) none of these

The value of tan {sin^(-1)(cos(sin^(-1)x))} tan{cos^(-1) (sin(cos^(-1)x))} x in (0,1) a)0 b)1 c)-1 d)None of these

The algebraic expression for f(x)=tan(sin^(-1)(cos("tan"^(-1)(x)/(2)))) is