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From the top of a tower of height 200 m,...

From the top of a tower of height 200 m, a ball A is projected up with speed `10ms^(-1)` and 2 s later, another ball B is projected vertically down with the same speed. Then

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From the top of a tower of height 200 m , a ball A is projected up with 10 m s^(-1) . And 2 s later another ball B is projected verticall down with the same speed. Then .

From the top of a tower of height 200 m , a ball A is projected up with 10 m s^(-1) . And 2 s later another ball B is projected verticall down with the same speed. Then .

From the top of a tower of height 40m, a ball is projected upward with a speed of 20ms^(-1) at an angle of elevation of 30^(@) . Then the ratio of the total time taken by the ball to hit the ground to the time taken to ball come at same level as top of tower.

From the top of a tower of height 40m, a ball is projected upward with a speed of 20ms^(-1) at an angle of elevation of 30^(@) . Then the ratio of the total time taken by the ball to hit the ground to the time taken to ball come at same level as top of tower.

From the top of a tower of height 40m, a ball is projected upward with a speed of 20ms^(-1) at an angle of elevation of 30^(@) . Then the ratio of the total time taken by the ball to hit the ground to the time taken to ball come at same level as top of tower.

From the top of a tower 100m in height, a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 25ms^-1 . Find when and where two balls will meet.

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

A ball is projected vertically up with speed 20 m/s. Take g=10m//s^(2)

From the top of a tower 100 m in height, a ball is dropped and at the same time another ball is projected vertically upwards from the ground with a velocity of 25 "m.s"^(-1) . Find when and where the two balls meet. Take g = 9.8 "m.s"^(-2) .