If `y = y(x)` and it follows the relation `e^(xy) + y cos x = 2`, then find (i) `y'(0)` and (ii) `y"(0)`.

If y=y(x) and it follows the relation x cos y+y cos x=pi then y'(0) is

If y=y(x) and it follows the relation e^(xy^(2))+y cos(x^(2))=5 then y'(0) is equal to

If y=y(x) and it follows the relation 4xe^(xy)=y+5sin^(2)x, then y'(0) is equal to

If log(x+y)=2xy, then y'(0) is

If y=y(x) is the solution of the equation e^(sin y) cos y""(dy)/(dx) +e^(sin y) cos x = cos x,y (0)=0, then 1+y ((pi)/(6)) +( sqrt(3))/(2) y((pi)/(3)) +(1)/( sqrt(2)) y((pi)/(4)) is equal to

If y = y ( x ) is the solution of differential equation sin y (dy ) /(dx ) - cos y = e ^ ( - x ) such that y ( 0 ) = ( pi ) /(2) then y (A) is equal to

Find the slope and y-intercept of the st.line in each of the following : (i) x+y=0 (ii) y+2=0 (iii) (y)/(x)=2 (iv)5x+6y=7

If log(x+y)=2xy then y'(0)=