A small object of mass of 100 g moves in a circular path . At a given instant velocity of the object is `10hati m s^(-1)` and acceleration is `(20hati+10hatj) m s^(-2)`. At this instant of time. the rate of change of kinetic energy of the object is

A small object of mass of 100 g moves in a circular path. At a given instant velocity of the object is 10hatim//s and acceleration is (20hati+10hatj)m//s^(2) . At this instant of time, rate of change of kinetic energy (in "kg m"^(2)s^(-3) ) of the object is

An object of mass 1 kg is moving with a velocity 10 m/s. Find the kinetic energy of the object

An object of 10 kg is moving with a speed of 2 m/s. The kinetic energy of the object is:

A particle is moving in an isolated x-y plane. At an instant, the particle has velocity (4hati+4hatj)m//s and acceleration (3hati+5hatj)m//s^(2) . At that instant what will be the radius of curvature of its path ?

A particle is moving on a circular path of 10 m radius. At any instant of time, its speed is 5ms^(-1) and the speed is increasing at a rate of 2ms^(-2) . At this instant, the magnitude of the net acceleration will be

A particle is moving on a circular path of 10 m radius. At any instant of time, its speed is 5ms^(-1) and the speed is increasing at a rate of 2ms^(-2) . At this instant, the magnitude of the net acceleration will be

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is

The initial velocity of an object is vecu = 5hati + 10hatj m//s . Its constant acceleration is veca = 2hati+ 3 hatj m//s^2 . Determine the velocity and the displacement after 5 s.