Let `f(x)={x+2,-1lelt0`
`1,x=0
(x)/(2),0ltxle1`

Let f(x)={(x+2,-1lexle0),(1,x=0),(x/2,0ltxle1):} Then on [-1,1] this function has

Let f(x)={(x+1, -1lexle0),(-x,0ltxle1):} then

Let f(x)={(x+1, -1lexle0),(-x,0ltxle1):} then

Let f(x)={{:(-2",",-3lexle0),(x-2",",0ltxle3):}andg(x)=f(|x|)+|f(x)| Which of the following statement is/are correct? 1. g(x) is differentiable x=0. g(x) is differentiable at x=2. Select the correct aswer using the code given below:

f(x)={(x-1, -1lexlt0),(x^2, 0ltxle1):} and g(x)=sin x. Then find h(x)=f(|g(x)|)+|f(g(x))|

If f(x) is defined as f(x)={{:(x,0lexlt(1)/(2)),(0,x=(1)/(2)),(1-x,(1)/(2)ltxle1):} then evaluate : lim_(xrarr(1)/(2)) f(x)

Let f(x)={:{(x^(2)+4x",",-3lexle0),(-sinx",",0ltxle(pi)/(2)),(-cosx-1",",(pi)/(2)ltxlepi):} then

Let f(x)={:{(x^(2)+4x",",-3lexle0),(-sinx",",0ltxle(pi)/(2)),(-cosx-1",",(pi)/(2)ltxlepi):} then

Let f(x)={:{(x^(2)+4x",",-3lexle0),(-sinx",",0ltxle(pi)/(2)),(-cosx-1",",(pi)/(2)ltxlepi):} then

Discuss the continuity of the function f(x)= {(x , 0 le x lt1/2 ),( 12,x=1/2),( 1-x , 1/2ltxle1):} at the point x=1//2 .