Find the depression of the miniscus in the capillary tube of diametre `0.4mm` dipped in a beaker containning mercury (density of mercury `=13.6xx10^(3)kg//m^(3)` and surface tension of the mercury is `0.49 N//m` and angle of contact is `135^(@)`).

Find the depression of the meniscus in the capillary tube of diameter 0.4 mm dipped in a beaker containing mercury. (Density of mercury = 13.6 times 10^3 kg m^-3 and surface tension of mercury = 0.49 Nm^-1 and angle of contact = 135^@ ).

Find the depression of mensicus in the when a capillary tube of diameter 0.2 mm is dipped in a beaker containg mercury. density of mercury is 13.6xx10^(-3)Kgm^(-3) , angle of contact is 130^(@) surface tension of mercury is 0.49Nm^(-1),g=9.8ms^(-2) .

A capillary tube of diameter 0.4mm is dipped in a beaker containing mercury. If density of mercury is 13.6 xx 10^3 kg//m^3 , surface tension 0.49Nm^(-1) , angle of contact 135^@ , the depression of the meniscus in the capillary tube will be

To what height can mercury be filled in a vessel without any leakage if there is a pin hole of diameter 0.1 mm at the bottom of the vessel? ( Density of mercury =13.6xx10^(3) kg m^(-3) , surface tension of mercury =550xx10^(-3) N m^(-1) , Neglect angle of contact.

A capillary tube of diameter 0.4 mm is dipped in a beaker containing mercury of density 13.6x10 3 kgm −3 and surface tension 0.49Nm −1 .The angle of contact of mercury w.r.t. glass is 130 o . [Cos 130 o = -0.64280]. The depression of the meniscus in the capillary tube is (g = 9.8 ms −2 ).

The excess pressure inside mercury drop of diameter 4 mm is (Take surface tension of mercury is 0.465 N/m)

A glass tube of 1 mm bore is dipped vertically into a container of mercury, with its lower end 5 cm below the mercury surface. What must be the gauge pressure of air in the tube to a hemispherical bubble at its lower end? Given density of mercury = 13.6 xx 10^(3) kg//m^(3) , surface tension of mercury = 440 xx 10^(-3) Nm^(-1) and g = 10m//s^(2)