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[hline20-40,40-70,70-110,110-180],[hline...

[hline20-40,40-70,70-110,110-180],[hline10,26,8,2],[hline]

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[" 8"," I "],[" M ",(1)/(*)],[,(4)/(4)],[,(9)/(2)],[,(9)/(9)],[,9],[hline,(4)/(3)],[+,9],[hline,1],[,7],[,3],[,9],[hline,1],[hline,-,(1)/(3)],[,,]

[" A parallel plate capacitor is "],[" constructed using three different "],[" dielectric materials as shown in fig."],[" The parallel plates across which a "],[" potential difference is applied are of "],[" area A and are separated by a "],[" distance d.The capacitance across A "],[" and B is "(xK in_(0)A)/(y)" .Find xy? ( "x,y" are "],[" smallest possible integers)."],[qquad [hline A,2k],[hline4k,k],[hline-d/2rarr A/2rarr]],[hline]

Calculate the arithmetic mean of the following frequency distribution by Direct Method: {:("Class Interval",10-20,20-40,40-70,70-120,120-200),("Frequency"," "4," "10," "26," "8," "2):}

Estimate the mode of the following data from the histogram. {:("Class Interval",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Frequency",8,10,15,16,20,13,14,12):}

For the given distribution, draw the less than and greater than cumulative frequency curves. {:("Class Interval",0-10,10-20,20-30,30-40,40-50,50-60,60-70,70-80),("Frequency",5,3,7,2,14,9,15,10):}

Calculate the median deviation from the median of the following data: Wages per week (in Rs.),10-20,20-30,30-40,40-50,50-60,60-70,70-80 No.of workers,4,6,10,20,10,6,4

Range of data: 20,40,30,60,80,100,10,70 is:

Range of data : 20,40,30,60,80,100,10,70 is

Given the following frequency distribution with some missing frequencies . {:("Class",10-20,20-30,30-40,40-50,50-60,60-70,70-80),(" "f," "180," "-," "34," "180," "136," "-," "50):} If the total frequency is 685 and median is 42.6 then the missing frequencies are