A circle is drawn with the two foci an ellipse `x^(2)/a^(2)+y^(2)/b^(2)=1` at the end of the diameter. What is the equation of the eircle ?

If the foci of an ellipse (x^(2))/(9)+(y^(2))/(16)=1 are ends of diameter of a circle then finds the radius of the circle

The equation of the circle drawn with the two foci of x^2/a^2+y^2/b^2=1 as the end-points of a diameter is

The equation of the circle drawn with the two foci of (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 as the end-points of a diameter is

The equation of the circle drawn with the two foci of (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 as the end -point of a diameter , is

Foci of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(alt b) are

A circle is drawn on the chord of a circle x^(2) + y^(2) =a^(2) as diameter. The chord lies on the line x+y = a . What is the equation of the circle ?

For the ellipse,(x^(2))/(a^(2))+(y^(2))/(b^(2))=1 the equation of the diameter conjugate ax-by=0 is-