" If "xy log(x+y)=1

(dy)/(dx)=(xy)/((1-x)(1+y)) A) x+y+log[y(1-x)]=c B) x+y+log[x(1-y)]=c C) x+y+log(x+y)=c D) y-x+log[x(1-y)]=c

If xy-log y=1,theny^(2)+(xy-1)(dy)/(dx)=

if x=y log(xy) then (dx)/(dy)=

If x^(2) + y^(2)=6xy , prove that 2 log (x+ y)= log x + log y + 3 log 2

x^2+y^2=log(xy)

Prove that : (iii) (yz)^(log(y/z))(zx)^(log(z/x))(xy)^(log(x/y)) = 1

xy log(x+y)=1, prove that (dy)/(dx)=-(y(x^(2)y+x+y))/(x(xy^(2)+x+y))

We can write log"" x/y = log (x.y^(-1 )) Can you prove that log"" x/y = log x - logy using product and power rules.