If `5^(log x)=50-x^(log5)` then `x=`

5^(log_(10)x)=50-x^(log_(10)5)

Solve for x:5^(log x)+5x^(log5)=3(a>0) where base oflog backslash is a

Solve for x:5^(log x)+5x^(log5)=3(a>0)

Solve for x: a) log_(x)2. log_(2x)2 = log_(4x)2 b) 5^(logx)+5x^(log5)=3(a gt 0), where base of log is 3.

If (3x)^(log3)=(5y)^(log5) and 5^(log x)=3^(log y) (all the log used have same base) then x & y are respectively:

Solve for x: 5^(log x) + 5x^(log 5) =3 (a>0)

Solve for x :5^(logx)+5x^(log5)=3(a >0); where base of log\ is a

Solve for x :5^(logx)+5x^(log5)=3(a >0); where base of log is a