Under the action of a force F = Cx, the position of a body changes from 0 to x. The work done is

A particle of mass 2 kg starts motion at time t = 0 under the action of variable force F = 4t (where F is in N and t is in s). The work done by this force in first two second is

A particle of mass 2 kg starts motion at time t = 0 under the action of variable force F = 4t (where F is in N and t is in s). The work done by this force in first two

A body covers a distance of 4m under the action of force F = (17 – 4x)N where x is the distance in metres. The work done by the force is

The relationship between the force Fand position x of a body is as shown in figure. The work done in displacing the body from x = 1 m to x = 5 m will be

A particale moves under the effect of a force F = Cx from x = 0 to x = x_(1) . The work down in the process is

The relationship between the force F and position x of body is as shown in figure. The work done in displacing the body from ( x = 1 m to x = 5 m ) will be .

The distance x covered by a body of 2 kg under the action of a force is related to time t as x=t^(2)//4 . What is the work done by this force in 2 seconds ?