" (iv) "(sin x+sec x)(cos x+cosec x)

Differentiate the following functions w.r.t. x : (sin x + sec x ) (cos x + cosec x)

For 0 lt x lt (pi)/(2),(sin x )/(cos x )*( sec x)/("cosec" x)*( tan x)/(cot x )=9 . Then x=

Find the derivative of the following functions: (i) sin x cos x (ii) sec x (iii) 5sec x+4 cos x (iv) cosec x (v) 3 cot x+5 cosec x (vi) 5sinx-6cosx+7 (vii) 2tanx-7secx

int(sec xdx)/(csc x(3+2cos x))

int (sec x cosec x)/(2 cot x- sec x cosec x)dx=

(sec^(8)x)/("cosec x")

If ( sin x ) /( cos x) xx ( sec x )/( cosec x ) xx ( tan x )/( cot x) = 9 , where x in ( 0, (pi)/(2)) then the value of x is equal to

int_(0)^(pi//2) (3 Sec x + 5 cosec x)/(Sec x + cosec x) dx=

int_(0)^((pi)/(2)) ("4 sec x + 5 cosec x")/("sec x + cosec x") dx

If cos((pi)/(4)-x)cos2x+sin x sin2x sec x=cos x sin2x sec x+cos((pi)/(4)+x)cos2x then possible value of sec x is